swift build -c release
Asked on 04/29/2025
1 search
The command swift build -c release
is used to build a Swift package in release configuration, which optimizes the build for performance. At WWDC 2024, there were several sessions that discussed improvements in Swift and Xcode that could impact how builds are handled.
In the session What’s new in Swift, improvements to how Xcode builds Swift code were highlighted. These improvements include better parallelism and more predictable builds through the use of explicitly built modules. This means that when you build your Swift code, the modules can be built in parallel, leading to faster and more efficient builds.
Additionally, the session What’s new in Xcode 16 introduced explicit modules, which are enabled by default for C and Objective-C, and can be opted into for Swift. This feature improves build performance by allowing better parallelism and faster debugging.
For more detailed information on explicitly built modules, you can refer to the session Demystify explicitly built modules, which explains how these modules work and how they can optimize your build process.
These sessions collectively provide insights into the advancements in build processes for Swift and Xcode, which can enhance the performance and efficiency of building Swift projects, especially in release configurations.

Analyze heap memory
Dive into the basis for your app’s dynamic memory: the heap! Explore how to use Instruments and Xcode to measure, analyze, and fix common heap issues. We’ll also cover some techniques and best practices for diagnosing transient growth, persistent growth, and leaks in your app.

Demystify explicitly built modules
Explore how builds are changing in Xcode 16 with explicitly built modules. Discover how modules are used to build your code, how explicitly built modules improve transparency in compilation tasks, and how you can optimize your build by sharing modules across targets.

Platforms State of the Union
Discover the newest advancements on Apple platforms.